JEE Main2017MathematicsStatisticsActual
A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is:
Options
- A12 5
- B6
- C4
- D6 25
Correct answer
A. 12 5
Step-by-step solution
For Bernoulli's trials Variance = n . p . q Given, number of trials n = 10 Probability of drawing a green ball p = 15 25 = 3 5 and q = 2 5 Hence, Variance = 10 × 3 5 × 2 5 = 12 5