JEE Main202528 Jan 2025Morning ShiftMathematicsVector AlgebraActual
Let a = i + j + k , b =2 i +2 j + k and d = a b . If c is a vector such that a c =| c | , | c -2 a |^2=8 and the angle between d and c is 4 , then |10-3 ~b c |+| d c |^2 is equal to
Correct answer
0
Step-by-step solution
aligned & a = i + j + k & b =2 i +2 j + k & d = a b & =- i + j & | c -2 a |^2=8 & | c |^2+4| a |^2-4 a c =8 & | c |^2+12-4| c |=8 & | c |^2-4| c |+4=0 & | c |^2=2 & d = a b & d c =( a b ) c & (| d | | c | 4 )^2=(( a c ) b -( b c ) a )^2 & 4=4| b |^2+( b c ) 2 (| a |^2 )-2( b c )( a b ) aligned Let b c =x aligned & 4=36+3 x^2-20 x & 3 x^2-20 x+32=0 & x= 8 3 , 4 & b c = 8 3 , 4 & b c = 8 3 aligned Now, |10-3 b c |+| d c |^2=|10-8|+(2)^2=6