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JEE Main 202431 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Vector Algebra

JEE Main 2024 · 31 January · Morning Shift · Mathematics · Vector Algebra

Let → a = 3 ^ i + ^ j - 2 ^ k , → b = 4 ^ i + ^ j + 7 ^ k and → c =...

Let \overset{\to}{a} = 3\overset{^}{i} + \overset{^}{j} - 2\overset{^}{k}, \overset{\to}{b} = 4\overset{^}{i} + \overset{^}{j} + 7\overset{^}{k} and \overset{\to}{c} = \overset{^}{i} - 3\overset{^}{j} + 4\overset{^}{k} be three vectors. If a vectors p→\overset{\to}{p} satisfies p→×b→=c→×b→\overset{\to}{p} \times \overset{\to}{b} = \overset{\to}{c} \times \overset{\to}{b} and p→⋅a→=0\overset{\to}{p} ⋅ \overset{\to}{a} = 0, then \overset{\to}{p} ⋅ \left(\overset{^}{i} - \overset{^}{j} - \overset{^}{k}\right) is equal to

Options

  1. A2424
  2. B3636
  3. C2828
  4. D3232

Correct answer

D. 3232

Step-by-step solution

Given: p→×b→=c→×b→\overset{\to}{p} \times \overset{\to}{b} = \overset{\to}{c} \times \overset{\to}{b}

⇒(p→−c→)×b→=0⇒ \left(\overset{\to}{p} - \overset{\to}{c}\right) \times \overset{\to}{b} = 0

⇒(p→−c→)∣∣b→⇒ \left(\overset{\to}{p} - \overset{\to}{c}\right) | | \overset{\to}{b}

⇒(p→−c→)=kb→⇒ \left(\overset{\to}{p} - \overset{\to}{c}\right) = k\overset{\to}{b}

⇒p→=kb→+c→⇒ \overset{\to}{p} = k\overset{\to}{b} + \overset{\to}{c}

⇒ \overset{\to}{p} = \left(4k + 1\right)\overset{^}{i} + \left(k - 3\right)\overset{^}{j} + \left(7k + 4\right)\overset{^}{k}

Now, p→.a→=0\overset{\to}{p} . \overset{\to}{a} = 0

⇒3(4k+1)+(k−3)−2(7k+4)=0⇒ 3\left(4k + 1\right) + \left(k - 3\right) - 2\left(7k + 4\right) = 0

⇒k=−8⇒ k = - 8

⇒ \overset{\to}{p} = - 31\overset{^}{i} - 11\overset{^}{j} - 52\overset{^}{k}

⇒ \overset{\to}{p} . \left(\overset{^}{i} - \overset{^}{j} - \overset{^}{k}\right) = - 31 + 11 + 52

⇒ \overset{\to}{p} . \left(\overset{^}{i} - \overset{^}{j} - \overset{^}{k}\right) = 32

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