An arc P Q of a circle subtends a right angle at its centre O . The mid point of the arc P Q is R . If O P → = u → , O R → = v → and O Q → = α u → + β v → , then α , β 2 , are the roots of the equation

Step-by-step solution

Given, An arc P Q of a circle subtends a right angle at its centre O . The mid point of the arc P Q is R , And O P → = u → ,   O R → = v → and O Q → = α u → + β v → , So, plotting the diagram of the given value we get, Now given, O Q → = α u → + β v → Where, O R   → = v → and O P   → = u → Now O P   → = O Q   → = radius , so R will lie on angle bisector of O Q → and O P