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JEE Main 202228 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Vector Algebra

JEE Main 2022 · 28 July · Evening Shift · Mathematics · Vector Algebra

Let S be the set of all a ∈ R for which the angle between the...

Let SS be the set of all a∈Ra \in R for which the angle between the vectors \overset{\to}{u} = a\left(\log_{e}b\right)\overset{^}{i} - 6\overset{^}{j} + 3\overset{^}{k} and \overset{\to}{v} = \left(\log_{e}b\right)\overset{^}{i} + 2\overset{^}{j} + 2a\left(\log_{e}b\right)\overset{^}{k}, \left(b > 1\right) is acute. Then SS is equal to

Options

  1. A(−∞,−43)\left(- \infty , - \dfrac{4}{3}\right)
  2. BΦΦ
  3. C(−43,0)\left(- \dfrac{4}{3}, 0\right)
  4. D(127,∞)\left(\dfrac{12}{7}, \infty\right)

Correct answer

B. ΦΦ

Step-by-step solution

Given,

\overset{\to}{u} = a\left(\log_{e}b\right)\overset{^}{i} - 6\overset{^}{j} + 3\overset{^}{k} and \overset{\to}{v} = \left(\log_{e}b\right)\overset{^}{i} + 2\overset{^}{j} + 2a\left(\log_{e}b\right)\overset{^}{k}

For angle to be acute u→⋅v→>0\overset{\to}{u} \cdot \overset{\to}{v} > 0

⇒ \left(a\left(\log_{e}b\right)\overset{^}{i} - 6\overset{^}{j} + 3\overset{^}{k}\right) . \left(\left(\log_{e}b\right)\overset{^}{i} + 2\overset{^}{j} + 2a\left(\log_{e}b\right)\overset{^}{k}\right) > 0

⇒a(log⁡eb)2−12+6a(log⁡eb)>0⇒ a{\left(\log_{e}b\right)}^{2} - 12 + 6a\left(\log_{e}b\right) > 0 ∀b>1\forall b > 1

Let y=a(log⁡eb)2−12+6a(log⁡eb)y = a{\left(\log_{e}b\right)}^{2} - 12 + 6a\left(\log_{e}b\right)

Now let log⁡eb=t⇒t>0\log_{e}b = t ⇒ t > 0 as b>1b > 1

Now y=at2+6at−12>0,∀t>0y = a{t}^{2} + 6at - 12 > 0, \forall t > 0

Since y>0y > 0, so a>0 and D<0a > 0 \text{ and } D < 0

⇒D=36a2+48a<0⇒ D = 36{a}^{2} + 48a < 0

⇒a∈⇒ a \in\left(\dfrac{- 4}{3}, 0\right)butbuta > 0,</p><p>So,,</p><p>So,a \in ϕ

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