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JEE Main 20211 SeptemberEvening Shift
Exam
JEE Main
Year
2021
Date
1 September
Shift
Evening Shift
Subject
Mathematics
Chapter
Vector Algebra

JEE Main 2021 · 1 September · Evening Shift · Mathematics · Vector Algebra

Let → a = 2 ^ i - ^ j + 2 ^ k and → b = ^ i + 2 ^ j - ^ k . Let a...

Let \overset{\to}{a} = 2\overset{^}{i} - \overset{^}{j} + 2\overset{^}{k} and \overset{\to}{b} = \overset{^}{i} + 2\overset{^}{j} - \overset{^}{k} . Let a vector v→\overset{\to}{v} be in the plane containing a→\overset{\to}{a} and b→.\overset{\to}{b} . If v→\overset{\to}{v} is perpendicular to the vector 3\overset{^}{i} + 2\overset{^}{j} - \overset{^}{k} and its projection on a→\overset{\to}{a} is 1919 units, then ∣2v→∣2| 2\overset{\to}{v}{|}^{2} is equal to _____.

Correct answer

0

Step-by-step solution

v→,a→,b→\overset{\to}{v}, \overset{\to}{a}, \overset{\to}{b} are coplanar

v→=λa→+μb→\overset{\to}{v} = \lambda\overset{\to}{a} + \mu\overset{\to}{b}
\overset{\to}{v} = \left(2\lambda + \mu\right)\overset{^}{i} + \left(2\mu - \lambda\right)\overset{^}{j} + \left(2\lambda - \mu\right)\overset{^}{k}

given \overset{\to}{v} ⊥\left(3\overset{^}{i} + 2\overset{^}{j} - \overset{^}{k}\right)

\overset{\to}{v} \cdot \left(3\overset{^}{i} + 2\overset{^}{j} - \overset{^}{k}\right) = 0

⇒ ( \left(2\lambda + \mu\right)\overset{^}{i} + \left(2\mu - \lambda\right)\overset{^}{j} + \left(2\lambda - \mu\right)\overset{^}{k} ) . ( 3\overset{^}{i} + 2\overset{^}{j} - \overset{^}{k} ) = 0

⇒3(2λ+μ)+2(2μ−λ)−(2λ−μ)=0⇒ 3 ( 2\lambda + \mu ) + 2 ( 2\mu - \lambda ) - ( 2\lambda - \mu ) = 0

⇒λ=−4μ...(i)⇒ \lambda = - 4\mu . . . ( i )

and also \overset{\to}{v} \cdot \overset{^}{a} = 19 ⇒ 9\lambda - 2\mu = 57 . . . \left(ii\right)

solving (i)and(ii)( i ) and ( ii ) we get

λ=6,μ=−32\lambda = 6, \mu = - \dfrac{3}{2}
⇒ 2\overset{\to}{v} = 21\overset{^}{i} - 18\overset{^}{j} + 27\overset{^}{k}
⇒∣2v→∣2=441+324+729⇒ | 2\overset{\to}{v}{|}^{2} = 441 + 324 + 729
=1494= 1494

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