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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Vector Algebra

JEE Main 2021 · 26 August · Evening Shift · Mathematics · Vector Algebra

If the projection of the vector ^ i + 2 ^ j + ^ k on the sum of the...

If the projection of the vector \overset{^}{i} + 2\overset{^}{j} + \overset{^}{k} on the sum of the two vectors 2\overset{^}{i} + 4\overset{^}{j} - 5\overset{^}{k} and - \lambda\overset{^}{i} + 2\overset{^}{j} + 3\overset{^}{k} is 11, then λ\lambda is equal to _______.

Correct answer

0

Step-by-step solution

Sum of two vectors = 2\overset{^}{i} + 4\overset{^}{j} - 5\overset{^}{k} + ( - \lambda\overset{^}{i} + 2\overset{^}{j} + 3\overset{^}{k} ) = ( 2 - \lambda ) \overset{^}{i} + 6\overset{^}{j} - 2\overset{^}{k}
Projection =1=1(2−λ)+2(6)+1×(−2)(2−λ)2+62+22= 1 = \dfrac{1 ( 2 - \lambda ) + 2 ( 6 ) + 1 \times ( - 2 )}{\sqrt{( 2 - \lambda{)}^{2} + {6}^{2} + {2}^{2}}}

⇒12−λλ2−4λ+44=1⇒ \dfrac{12 - \lambda}{\sqrt{{\lambda}^{2} - 4\lambda + 44}} = 1
⇒(12−λ)2=λ2−4λ+44⇒ ( 12 - \lambda{)}^{2} = {\lambda}^{2} - 4\lambda + 44
⇒144+λ2−24λ=λ2−4λ+44⇒ 144 + {\lambda}^{2} - 24\lambda = {\lambda}^{2} - 4\lambda + 44
⇒100=20λ⇒ 100 = 20\lambda
⇒λ=5⇒ \lambda = 5

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