Let a → and b → be two non-zero vectors perpendicular to each other and | a → | = | b → | , If | a → × b → | = | a → | , then the angle between the vectors ( a → + b → + ( a → × b → ) ) and a → is equal to :

Step-by-step solution

| a → | = | b → | , | a → × b → | = | a → | , a → ⊥ b → | a → × b → | = | a → | ⇒ | a → | | b → | sin 90 ° = | a → | ⇒ | b → | = 1 = | a → | a → and b → are mutually perpendicular unit vectors. Let a → = i ^ , b → = j ^ ⇒ a → × b → = k ^ cos θ = ( i ^ + j ^ + k ^ ) i ^ 3 1 = 1 3 ⇒ θ = cos - 1 1 3