JEE Main2004MathematicsVector AlgebraActual
A velocity 1 4 ~m / s is resolved into two components along OA and OB making angles 30^ and 45^ respectively with the given velocity. Then the component along OB is
Options
- A1 8 ~m / s
- B1 4 ( 3 -1) m / s
- C1 4 ~m / s
- D1 8 ( 6 - 2 ) m / s
Correct answer
D. 1 8 ( 6 - 2 ) m / s
Step-by-step solution
Component along OB = 1 4 30^ (45^ +30^ ) = 1 8 ( 6 - 2 ) m / s .