JEE Main202623 January 2026Morning ShiftPhysicsAlternating CurrentActual
Using a variable frequency a.c. voltage source the maximum current measured in the given LCR circuit is 50 mA for V=5 (100 t) The values of L and R are shown in the figure. The capacitance of the capacitor (C) used is _ _ _ _ F .
Options
- ABoth Statement I and Statement II are true
- BBoth Statement I and Statement II are false
- CStatement I is true but Statement II is false
- DStatement I is false but Statement II is true
Correct answer
D. Statement I is false but Statement II is true
Step-by-step solution
From V = 5 (100t) , angular frequency = 100 rad/s At resonance in LCR circuit: X_L = X_C , so L = 1 C Maximum current occurs at resonance: I_ max = V_ rms R 50 10⁻³ = 5/ 2 100 (verified at resonance) From resonance condition: 100 2 = 1 100 C 200 = 1 100C C = 1 20000 = 5 10⁻⁵ F = 50 μF