An inductor of self inductance 1 H connected in series with a resistor of 100 ohm and an ac supply of 100 volt, 50 Hz. Maximum current flowing in the circuit is ________ A.

Step-by-step solution

Impedance of circuit aligned & Z = R ^2+ ( X _ L )^2 = R ^2+ ( _ L )^2 & = (100 )^2+(2 50 1)^2 & = (100 )^2+(100 )^2 & = 2 100 & I _ rms = V 2 = 100 2 100 = 1 2 & I _ = 2 I _ rms = 2 1 2 =1 Ampere aligned Correct Answer : 1