JEE Main 202524 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Alternating Current
JEE Main 2025 · 24 January · Morning Shift · Physics · Alternating Current
An alternating current is given by I= I _ A ω t+ I _ B ω t . The...
An alternating current is given by \mathrm{I}\mathrm{I}. The r.m.s current will be
Options
- A\frac{\left|\mathrm{I}\mathrm{I}_{\mathrm{B}}\right|}{\sqrt{2}}
- B\sqrt{\frac{\mathrm{I}\mathrm{I}_{\mathrm{B}}^2}{2}}
- C\sqrt{\mathrm{I}\mathrm{I}_{\mathrm{B}}^2}
- D\frac{\sqrt{\mathrm{I}\mathrm{I}_{\mathrm{B}}^2}}{2}
Correct answer
B. \sqrt{\frac{\mathrm{I}\mathrm{I}_{\mathrm{B}}^2}{2}}