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JEE Main20248 Apr 2024Evening ShiftPhysicsAlternating CurrentActual

A coil of negligible resistance is connected in series with 90 resistor across 120 ~V , 60 ~Hz supply. A voltmeter reads 36 ~V across resistance. Inductance of the coil is :

Options

  1. A0.286 H
  2. B0.76 H
  3. C2.86 H
  4. D0.91 H

Correct answer

B. 0.76 H

Step-by-step solution

aligned & 36=I_ rms R & 36= 120 X _ L ^2+ R ^2 R & R =90 36= 120 90 X _ L ^2+90^2 & X _ L ^2+90^2 =300 & X _ L ^2=81900 & X _ L =286.18 & L =286.18 & ~L = 286.18 376.8 & ~L =0.76 H aligned

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