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JEE Main 20248 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2024 · 8 April · Morning Shift · Physics · Alternating Current

A LCR circuit is at resonance for a capacitor C , inductance L and...

A LCR circuit is at resonance for a capacitor CC, inductance LL and resistance RR. Now the value of resistance is halved keeping all other parameters same. The current amplitude at resonance will be now:

Options

  1. AZero
  2. Bsame
  3. Chalved
  4. Ddouble

Correct answer

D. double

Step-by-step solution

In resonance Z=RZ=RI=VRR→ halved ⇒I→2I\begin{aligned} & \mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}} \\ & \mathrm{R} \rightarrow \text{ halved } \\ & \Rightarrow \mathrm{I} \rightarrow 2 \mathrm{I}\end{aligned}$$ I becomes doubled.
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