JEE Main20241 Feb 2024Evening ShiftPhysicsAlternating CurrentActual
A transformer has an efficiency of 80 % and works at 10 V and 4 kW . If the secondary voltage is 240 V , then the current in the secondary coil is:
Options
- A1 . 59 A
- B13 . 33 A
- C1 . 33 A
- D15 . 1 A
Correct answer
B. 13 . 33 A
Step-by-step solution
Efficiency η = P o u t p u t P i n p u t = E S I S E P I P ⇒ 0 . 8 = 240 I S 4000 ⇒ I S = 3200 240 = 13 . 33 A