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JEE Main202430 Jan 2024Evening ShiftPhysicsAlternating CurrentActual

An alternating voltage V ( t ) = 220 sin 100 π t volt is applied to a purely resistive load of 50 Ω . The time taken for the current to rise from half of the peak value to the peak value is:

Options

  1. A5 ms
  2. B3 . 3 ms
  3. C7 . 2 ms
  4. D2 . 2 ms

Correct answer

B. 3 . 3 ms

Step-by-step solution

Time taken to change current value from half of the peak value to the peak value is, t = T 6 ⇒ t = 2 π 6 ω = π 3 ω = π 300 π = 1 300 = 3 . 33 ms

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