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JEE Main 202430 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2024 · 30 January · Evening Shift · Physics · Alternating Current

An alternating voltage V ( t ) = 220 100 volt is applied to a...

An alternating voltage V(t)=220sin⁡100\pitV ( t ) = 220\sin 100\pit volt is applied to a purely resistive load of 50Ω50Ω. The time taken for the current to rise from half of the peak value to the peak value is:

Options

  1. A5ms5ms
  2. B3.3ms3 . 3ms
  3. C7.2ms7 . 2ms
  4. D2.2ms2 . 2ms

Correct answer

B. 3.3ms3 . 3ms

Step-by-step solution

Time taken to change current value from half of the peak value to the peak value is, 

t=T6t = \dfrac{T}{6}

⇒t=2π6ω=π3ω=π300π=1300=3.33ms⇒ t = \dfrac{2\pi}{6\omega} = \dfrac{\pi}{3\omega} = \dfrac{\pi}{300\pi} = \dfrac{1}{300} = 3 . 33ms

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