A series LCR circuit has L = 0 . 01 H , R = 10 Ω and C = 1 μ F and it is connected to ac voltage of amplitude V m 50 V . At frequency 60 % lower than resonant frequency, the amplitude of current will be approximately

Step-by-step solution

For an LCR circuit. the resonant angular frequency is given by, ω 0 = 1 L C = 10 4   rad   s - 1 The given frequency is 60 % lower than resonant frequency. Therefore, ω ' = 0 . 4 × 10 4 = 4000   rad   s - 1 Reactance of the capacitor at given frequency, X C = ω ' C - 1 = 250   Ω . Reactance of the inductor at given frequency, X L = ω ' L = 40   Ω Now the amplitude of the current in the given circuit will be, i 0 = V 0 R 2 + X C ' - X L &#3