The effective current I in the given circuit at very high frequencies will be _____ A .

Step-by-step solution

At very high frequencies, inductor acts as an open circuit and capacitor as short circuit. So, capacitive reactance, X C = 1 ω C ≈ 0 Also, inductive reactance, X L = ω L ≈ ∞ Thus, equivalent circuit can be redrawn as Here, both 4 Ω resistances are in parallel and together they are in series with 1 Ω and 2 Ω resistances. Equivalent impedance is Z = 1 + 4 × 4 4 + 4 + 2 = 5 Ω Effective current is I = 220 V 5 Ω = 44 A