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JEE Main202225 Jul 2022Morning ShiftPhysicsAlternating CurrentActual

The RMS value of conduction current in a parallel plate capacitor is 6 . 9 μ A . The capacity of this capacitor, if it is connected to 230 V AC supply with an angular frequency of 600 rad s - 1 , will be

Options

  1. A5 pF
  2. B50 pF
  3. C100 pF
  4. D200 pF

Correct answer

B. 50 pF

Step-by-step solution

I rms = 6 . 9   μA ;   V rms = 230   V ;   ω = 600   rad   s - 1 Current in capacitor I rms = V rms X C , where, X C is capacitive reactance given by X C = 1 ω C Now, current, I rms = V rms × ω C So, capacitance is C = I rms V rms ω = 6 . 9 × 10 - 6 230 × 600 = 50   pF

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