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JEE Main202124 Feb 2021Morning ShiftPhysicsAlternating CurrentActual

A resonance circuit having inductance and resistance 2 × 10 - 4 H and 6 . 28 Ω respectively oscillates at 10 MHz frequency. The value of quality factor of this resonator is_______. π = 3 . 14

Correct answer

0

Step-by-step solution

Given: L = 2 × 10 - 4   H R = 6 . 28   Ω f = 10   MHz = 10 7   Hz Since quality factor, Q = ω 0 L R = 2 π f L R ∴     Q = 2 π × 10 7 × 2 × 10 - 4 6 . 28 Q = 2 × 10 3 = 2000

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