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JEE Main 20209 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
9 January
Shift
Evening Shift
Subject
Physics
Chapter
Alternating Current

JEE Main 2020 · 9 January · Evening Shift · Physics · Alternating Current

Two identical capacitors A and B, charged to the same potential 5V...

Two identical capacitors AA and B,B, charged to the same potential 5V5V are connected in two different circuits as shown below at time t=0.t = 0 . If the charge on capacitors AA and BB at time t=CRt = CR is QA{Q}_{A} and QB{Q}_{B} respectively, then (Here ee is the base of natural logarithm)

Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown

Options

  1. AQA=VCe,QB=CV2{Q}_{A} = \dfrac{VC}{e}, {Q}_{B} = \dfrac{CV}{2}
  2. BQA=VC,QB=CV{Q}_{A} = VC, {Q}_{B} = CV
  3. CQA=VC,QB=VCe{Q}_{A} = VC, {Q}_{B} = \dfrac{VC}{e}
  4. DQA=CV2,QB=VCe{Q}_{A} = \dfrac{CV}{2}, {Q}_{B} = \dfrac{VC}{e}

Correct answer

C. QA=VC,QB=VCe{Q}_{A} = VC, {Q}_{B} = \dfrac{VC}{e}

Step-by-step solution

Charge on capacitor after charging with a battery of potential VV, Q=CVQ = CV

Now, capacitor AA is connected as shown in the figure.

Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown

As diode is in reverse bias, so capacitor charge remains same after time t=CRt = CR.

∴QA=CV∴ {Q}_{A} = CV

In case BB, capacitor is connected as shown in the figure.

Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown

Here, diode is in forward bias, so capacitor discharges and its charge decays as

QB=Q⋅e−tRC{Q}_{B} = Q \cdot e\dfrac{- t}{RC}

where, t=RCt = RC

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