A series A C circuit containing an inductor 20 mH , a capacitor 120 μ F and a resistor 60 Ω is driven by an A C source of 24 V / 50 Hz . The energy dissipated in the circuit in 60 s is:

Step-by-step solution

(Power factor), P f = cos ⁡ ϕ = R Z Where R ,   Z are the resistance and impedance respectively. (Energy dissipated) E = V r m s 2 Z × cos ϕ × t ⇒ E = V r m s 2 Z × R Z × t ⇒ E = V r m s 2 Z 2 × R × t V r m s ,   t are the RMS voltage and time respectively. We know that the Impedance of an LCR circuit is given by the formula,           Z 2 = R 2 + ω L - 1 ω C 2 ⇒ Z 2 = 60 2 + 2 π × 50 × 20 &#21