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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Physics
Chapter
Alternating Current

JEE Main 2014 · 6 April · Physics · Alternating Current

In the circuit shown here, the point ' C ' is kept connected to...

In the circuit shown here, the point 'CC' is kept connected to point AA '' till the current flowing through the circuit becomes constant. Afterward, suddenly, point 'CC' is disconnected from point AA '' and connected to point 'BB' at time t=0t = 0. Ratio of the voltage across resistance and the inductor at t=LRt = \dfrac{L}{R} will be equal to :

In the circuit shown here, the point ' C ' is kept connected to point A '' till the current flowing through the circuit

Options

  1. Ae1−e\dfrac{\text{e}}{1 - \text{e}}
  2. B1
  3. C- 1
  4. D1−ee\dfrac{1 - \text{e}}{\text{e}}

Correct answer

C. - 1

Step-by-step solution

Applying Kirchhoff's law in closed loop,

−VR−VL=0- {V}_{R} - {V}_{L} = 0

⇒VRVL=−1⇒ \dfrac{{V}_{R}}{{V}_{L}} = - 1

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