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JEE Main 20139 AprilOnline
Exam
JEE Main
Year
2013
Date
9 April
Mode
Online
Subject
Physics
Chapter
Alternating Current

JEE Main 2013 · 9 April · Online · Physics · Alternating Current

In the circuit shown here, the voltage across E and C are...

In the circuit shown here, the voltage across E\mathrm{E} and C\mathrm{C} are respectively 300 V300 \mathrm{~V} and 400 V400 \mathrm{~V}. The voltage E\mathrm{E} of the ac source is : In the circuit shown here, the voltage across E and C are respectively 300 ~V and 400 ~V . The voltage E of the ac

Options

  1. A400400 Volt
  2. B500500 Volt
  3. C100100 Volt
  4. D700700 Volt

Correct answer

C. 100100 Volt

Step-by-step solution

Voltage EE of the ac source E=VC−VL=400 V−300 V=100 V\begin{aligned} & E=V_C-V_L \\ & =400 \mathrm{~V}-300 \mathrm{~V}=100 \mathrm{~V} \end{aligned}
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