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JEE Main 2006
Exam
JEE Main
Year
2006
Subject
Physics
Chapter
Alternating Current

JEE Main 2006 · Physics · Alternating Current

In a series resonant LCR circuit, the voltage across R is 100 volts...

In a series resonant LCR circuit, the voltage across RR is 100 volts and R=1kΩR=1 \mathrm{k} \Omega with C=2μFC=2 \mu \mathrm{F}. The resonant frequency ω\omega is 200rad/s200 \mathrm{rad} / \mathrm{s}. At resonance the voltage across LL is

Options

  1. A4×10−3 V4 \times 10^{-3} \mathrm{~V}
  2. B2.5×10−2 V2.5 \times 10^{-2} \mathrm{~V}
  3. C40 V40 \mathrm{~V}
  4. D250 V250 \mathrm{~V}

Correct answer

D. 250 V250 \mathrm{~V}

Step-by-step solution

i=1001000=0.1 A\mathrm{i}=\frac{100}{1000}=0.1 \mathrm{~A} VL=VC=0.1200×2×10−6=250 VV_L=V_C=\frac{0.1}{200 \times 2 \times 10^{-6}}=250 \mathrm{~V}
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