The smallest wavelength of Lyman series is 91 nm. The difference between the largest wavelengths of Paschen and Balmer series is nearly _ _ _ _ nm .

Step-by-step solution

Smallest wavelength of lyman 1 = R ( 1 1^2 - 1 ^2 ) R = 1 = 1 91 nm ⁻¹ _ max for balmer series n₁ = 2 n₂ = 3 1 _B = R ( 1 4 - 1 9 ) 1 _B = 1 91 ( 5 36 ) _B = ( 91 36 5 ) = 655.2 nm _ max paschen n₁ = 3 n₂ = 4 1 _p = 1 91 ( 1 3^2 - 1 4^2 ) = 1 91 7 144 _p = ( 91 144 7 ) = 1872 nm = _P - _B = 1872 - 655.2 = 1216.8 1217