During the transition of electron from state A to state C of a Bohr atom, the wavelength of emitted radiation is 2000 Å and it becomes 6000 Å when the electron jumps from state B to state C. Then the wavelength of the

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Correct answer: C. 3000 Å

(h c)/(λ_1)=E_0 z^2 ((1)/(n_c^2)-(1)/(n_A^2)) ....(i) And (h c)/(λ_2)=E_0 z^2 ((1)/(n_c^2)-(1)/(n_B^2)) So for A and B ....(ii) (h c)/(λ_3)=E_0 z^2 ((1)/(n_B^2)-(1)/(n_A^2)) Clearly subtracting equation (ii) from equation (i) aligned & h c[(1)/(λ_1)-(1)/(λ_2)]=E_0 z^2[(1)/(n_B^2)-(1)/(n_A^2)]=(h c)/(λ_3) & (1)/(λ_3)=(1)/(λ_1)-(1)/(λ_2) (1)/(λ_3)=((6000-2000))/(6000 × 2000)=(1)/(3000) & λ_3=3000 Å aligned

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