JEE Main202524 Jan 2025Morning ShiftPhysicsAtomic PhysicsActual
During the transition of electron from state A to state C of a Bohr atom, the wavelength of emitted radiation is 2000 Å and it becomes 6000 Å when the electron jumps from state B to state C. Then the wavelength of the radiation emitted during the transition of electrons from state A to state B is
Options
- A4000 Å
- B2000 Å
- C3000 Å
- D6000 Å
Correct answer
C. 3000 Å
Step-by-step solution
h c ₁ =E₀ z^2 ( 1 n_c^2 - 1 n_A^2 ) ....(i) And h c ₂ =E₀ z^2 ( 1 n_c^2 - 1 n_B^2 ) So for A and B ....(ii) h c ₃ =E₀ z^2 ( 1 n_B^2 - 1 n_A^2 ) Clearly subtracting equation (ii) from equation (i) aligned & h c [ 1 ₁ - 1 ₂ ]=E₀ z^2 [ 1 n_B^2 - 1 n_A^2 ]= h c ₃ & 1 ₃ = 1 ₁ - 1 ₂ 1 ₃ = (6000-2000) 6000 2000 = 1 3000 & ₃=3000 Å aligned