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JEE Main 20238 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2023 · 8 April · Evening Shift · Physics · Atomic Physics

The ratio of wavelength of spectral lines H _ α and H _ β in the...

The ratio of wavelength of spectral lines Hα{H}_{\alpha} and Hβ{H}_{\beta} in the Balmer series is x20\dfrac{x}{20}. The value of xx is _____.

Correct answer

0

Step-by-step solution

The formula to calculate the wavelength of Hα{H}_{\alpha}-line in Balmer series is given by

hcλα=13.6[14−19]...(1)\dfrac{hc}{{\lambda}_{\alpha}} = 13 . 6\left[\dfrac{1}{4} - \dfrac{1}{9}\right] . . . \left(1\right)

The formula to calculate the wavelength of Hβ{H}_{\beta}-line in Balmer series is given by

hcλβ=13.6[14−116]...(2)\dfrac{hc}{{\lambda}_{\beta}} = 13 . 6\left[\dfrac{1}{4} - \dfrac{1}{16}\right] . . . \left(2\right)

Divide equation (2) by equation (1)
⇒λαλβ=14−11614−19⇒ \dfrac{{\lambda}_{\alpha}}{{\lambda}_{\beta}} = \dfrac{\dfrac{1}{4} - \dfrac{1}{16}}{\dfrac{1}{4} - \dfrac{1}{9}}
=3664×125= \dfrac{36}{64} \times \dfrac{12}{5}
=2720= \dfrac{27}{20}

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