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JEE Main 20236 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Morning Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2023 · 6 April · Morning Shift · Physics · Atomic Physics

The radius of fifth orbit of Li ^ + + is _______ × 10 ^ - 12 m ....

The radius of fifth orbit of Li++{Li}^{+ +} is_______ \times {10}^{- 12}m . Take: radius of hydrogen atom=0.51A∘= 0 . 51\overset{∘}{A}

Correct answer

0

Step-by-step solution

The formula to calculate the radius of Lithium-ion is given by

RLi=RH×n2Z...(1){R}_{Li} = {R}_{H} \times \dfrac{{n}^{2}}{Z} . . . ( 1 )

Substitute the values of the known parameters into equation (1) to calculate the required radius of the ion.

{RLi=0.51×253×10−10m=425×10−12m\begin{cases}{R}_{Li} & = & \dfrac{0 . 51 \times 25}{3} \times {10}^{- 10}m \\ & = & 425 \times {10}^{- 12}m\end{cases}

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