Nucleus a having Z = 17 and equal number of protons and neutrons has 1 . 2 MeV binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1 . 8 MeV binding energy per nucleons. The difference of binding energy of B and A will be ______ MeV .

Step-by-step solution

In A ,   Z = 17 and have equal numbers of protons and neutrons i.e. nucleons = 2 × 17 = 34 So, for A , Total binding energy B E A = 1 . 2 × 34 = 40 . 8   MeV Another nucleus B mass number = 26 So, total binding energy of B is B E B = 1 . 8 × 26   MeV = 46 . 8   MeV Difference of B E = B E B - B E A = 6   MeV