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JEE Main 202331 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Morning Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2023 · 31 January · Morning Shift · Physics · Atomic Physics

For hydrogen atom, λ _ 1 and λ _ 2 are the wavelengths...

For hydrogen atom, λ1{\lambda}_{1} and λ2{\lambda}_{2} are the wavelengths corresponding to the transitions 11 and 22 respectively as shown in figure. The ratio of λ1{\lambda}_{1} and λ2{\lambda}_{2} is x32\dfrac{x}{32}. The value of xx is ______.

For hydrogen atom, λ _ 1 and λ _ 2 are the wavelengths corresponding to the transitions 1 and 2 respectively as shown

Correct answer

0

Step-by-step solution

Wavelength corresponding to the photon emitted in transition n=3ton=1n = 3ton = 1 is

1λ1=R(112−132)=8R9\dfrac{1}{{\lambda}_{1}} = R\left(\dfrac{1}{{1}^{2}} - \dfrac{1}{{3}^{2}}\right) = \dfrac{8R}{9} ....(1)

Wavelength corresponding to the photon emitted for transition in transition n=2ton=1n = 2ton = 1 is

1λ2=R(112−122)=3R4\dfrac{1}{{\lambda}_{2}} = R\left(\dfrac{1}{{1}^{2}} - \dfrac{1}{{2}^{2}}\right) = \dfrac{3R}{4} ....(2)

λ1λ2=3R4×98R=2732\dfrac{{\lambda}_{1}}{{\lambda}_{2}} = \dfrac{3R}{4} \times \dfrac{9}{8R} = \dfrac{27}{32}

Hence, the value of x=27x = 27.

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