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JEE Main 202225 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
25 July
Shift
Evening Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2022 · 25 July · Evening Shift · Physics · Atomic Physics

(x)/(x + 4) is the ratio of energies of photons produced due to...

xx+4\dfrac{x}{x + 4} is the ratio of energies of photons produced due to transition of an electron of hydrogen atom from its

(i) third permitted energy level to the second level and

(ii) the highest permitted energy level to the second permitted level.

The value of xx will be

Correct answer

0

Step-by-step solution

Energy of a photon released in transition of electron in hydrogen atom is given by,

E=13.6(1n22−1n12)eVE = 13 . 6\left(\dfrac{1}{{{n}_{2}}^{2}} - \dfrac{1}{{{n}_{1}}^{2}}\right)eV

⇒E1E2=13.6(14−19)13.6(14−1∞)=xx+4⇒14−1914=xx+4⇒ \dfrac{{E}_{1}}{{E}_{2}} = \dfrac{13 . 6\left(\dfrac{1}{4} - \dfrac{1}{9}\right)}{13 . 6\left(\dfrac{1}{4} - \dfrac{1}{\infty}\right)} = \dfrac{x}{x + 4} ⇒ \dfrac{\dfrac{1}{4} - \dfrac{1}{9}}{\dfrac{1}{4}} = \dfrac{x}{x + 4}

⇒59=xx+4⇒ \dfrac{5}{9} = \dfrac{x}{x + 4}

⇒5x+20=9x⇒ 5x + 20 = 9x

⇒x=5⇒ x = 5

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