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JEE Main202126 Feb 2021Morning ShiftPhysicsAtomic PhysicsActual

If λ 1 and λ 2 are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of λ 1 : λ 2 is :

Options

  1. A7 : 135
  2. B1 : 9
  3. C1 : 3
  4. D7 : 108

Correct answer

A. 7 : 135

Step-by-step solution

1 λ 1 = R 1 1 2 - 1 4 2 1 λ 2 = R 1 3 2 - 1 4 2 λ 1 λ 2 = 1 9 - 1 16 1 - 1 16 = 7 9 × 15 λ 1 λ 2 = 7 135

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