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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Physics
Chapter
Atomic Physics

JEE Main 2021 · 24 February · Evening Shift · Physics · Atomic Physics

According to Bohr atom model, in which of the following transitions...

According to Bohr atom model, in which of the following transitions will the frequency be maximum?

Options

  1. An=3n = 3 to n=2n = 2
  2. Bn=5n = 5 to n=4n = 4
  3. Cn=4n = 4 to n=3n = 3
  4. Dn=2n = 2 to n=1n = 1

Correct answer

D. n=2n = 2 to n=1n = 1

Step-by-step solution

\DeltaE=13.6[1n12−1n22]=hv\DeltaE = 13 . 6\left[1{n}_{1}^{2} - 1{n}_{2}^{2}\right] = hv

It is maximum if n1=1{n}_{1} = 1 and n2=2{n}_{2} = 2

n=5………………………………..−0.544eVn = 5 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . . - 0 . 544eV

n=4....................................................−0.850eVn = 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . - 0 . 850eV

n=3…………………………………..−1.511eVn = 3 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . . - 1 . 511eV

n=2…………………………………−3.4eVn = 2 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots - 3 . 4eV

n=1………………………………….−13.6eVn = 1 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . - 13 . 6eV

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