JEE Main 2021 · 24 February · Evening Shift · Physics · Atomic Physics
D. n=2n = 2n=2 to n=1n = 1n=1
\DeltaE=13.6[1n12−1n22]=hv\DeltaE = 13 . 6\left[1{n}_{1}^{2} - 1{n}_{2}^{2}\right] = hv\DeltaE=13.6[1n12−1n22]=hv
It is maximum if n1=1{n}_{1} = 1n1=1 and n2=2{n}_{2} = 2n2=2
n=5………………………………..−0.544eVn = 5 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . . - 0 . 544eVn=5………………………………..−0.544eV
n=4....................................................−0.850eVn = 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . - 0 . 850eVn=4....................................................−0.850eV
n=3…………………………………..−1.511eVn = 3 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . . - 1 . 511eVn=3…………………………………..−1.511eV
n=2…………………………………−3.4eVn = 2 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots - 3 . 4eVn=2…………………………………−3.4eV
n=1………………………………….−13.6eVn = 1 \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots . - 13 . 6eVn=1………………………………….−13.6eV