In the line spectra of hydrogen atom, difference between the largest and the shortest wavelengths of the Lyman series is 305 A ∘ . The corresponding difference for the Paschan series in A ∘ is:________

Step-by-step solution

1 λ min = R 1 = R   ;   n = ∞ to 1 1 λ max = R 1 − 1 4 = 3 R 4 ; n = 2 to 1 ⇒ λ max − λ min = 4 3 R − 1 R 304 = 1 3 R ...... a Paschen : Y λ ' min = R 1 9 and Y λ ' max = R 1 9 − 1 16 = 7 R 16 × 9 λ ' max − λ ' min = 16 × 9 7 R − 9 R = 81 7 R ... b b a = x 3 × 304 = 81 7 ⇒ x = 10553 . 14