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JEE Main201912 Apr 2019Evening ShiftPhysicsAtomic PhysicsActual

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths λ 1 λ 2 of the photons emitted in this process is:

Options

  1. A7 5
  2. B20 7
  3. C9 7
  4. D27 5

Correct answer

B. 20 7

Step-by-step solution

1 λ 1 = R 1 3 2 - 1 4 2 = R × 7 144 1 λ 2 = R 1 2 2 - 1 3 2 = R × 5 36 ⇒ λ 1 λ 2 = R × 5 36 × 144 R × 7 = 20 7

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