Light is incident on a metallic plate having work function 110 × 10^ -20 ~J . If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is \_\_\_\_ rad/s. (h=6.63 × 10^ -34

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Correct answer: B. 1.04 × 10^ 16

From Einstein's photoelectric equation,

h\nu = W + KE

.
With zero kinetic energy,

h\nu = W

.
The frequency is

\nu = \frac{W}{h} = \frac{110 \times 10^{-20}}{6.63 \times 10^{-34}} = 16.59 \times 10^{14}

Hz.
The angular frequency is

\omega = 2\pi\nu = 2\pi \times 16.59 \times 10^{14}

= 104.25 \times 10^{14} = 1.04 \times 10^{16}

rad/s.

Light is incident on a metallic plate having work function 110 ×...

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