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JEE Main 202524 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Evening Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2025 · 24 January · Evening Shift · Physics · Dual Nature of Matter

In photoelectric effect, the stopping potential (V_0) v / s...

In photoelectric effect, the stopping potential (V0)v/s\left(\mathrm{V}_0\right) \mathrm{v} / \mathrm{s} frequency (ν)(\nu) curve is plotted. ( h is the Planck's constant and ϕ0\phi_0 is work function of metal ) (A) V0v/sν\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu is linear. (B) The slope of V0v/sν\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu curve =ϕ0 h=\frac{\phi_0}{\mathrm{~h}} (C) h constant is related to the slope of V0v/sν\mathrm{V}_0 \mathrm{v} / \mathrm{s} \nu line. (D) The value of electric charge of electron is not required to determine hh using the V0v/sνV_0 \mathrm{v} / \mathrm{s} \nu curve. (E) The work function can be estimated without knowing the value of hh. Choose the correct answer from the options given below :

Options

  1. A(C) and (D) only
  2. B(A), (C) and (E) only
  3. C(A), (B) and (C) only
  4. D(D) and (E) only

Correct answer

B. (A), (C) and (E) only

Step-by-step solution

hv=ϕ+KEmax⁡KEmax⁡=eV0 V0=hv−ϕe\begin{aligned} & \mathrm{hv}=\phi+\mathrm{KE}_{\max } \\ & \mathrm{KE}_{\max }=\mathrm{eV}_0 \\ & \mathrm{~V}_0=\frac{\mathrm{hv}-\phi}{\mathrm{e}} \end{aligned} (A) V0v/sV\mathrm{V}_0 \mathrm{v} / \mathrm{s} \mathrm{V} is linear correct (B) Slope v0=(he)v−ϕe Wrong \mathrm{v}_0=\left(\frac{\mathrm{h}}{\mathrm{e}}\right) \mathrm{v}-\frac{\phi}{\mathrm{e}} \text{ Wrong } Slope he\frac{h}{e} (C) Correct (D) Incorrect (E) Correct
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