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Average force exerted on a non-reflecting surface at normal incidence is 2.4 10⁻⁴ ~N . If 360 ~W / cm ^2 is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is:

Options

  1. A0.2 ~m ^2
  2. B20 ~m ^2
  3. C0.1 ~m ^2
  4. D0.02 ~m ^2

Correct answer

D. 0.02 ~m ^2

Step-by-step solution

aligned & Pressure = I C = F A & 360 10⁻⁴ 3 10^8 = 2.4 10⁻⁴ A & A =2 10⁻² ~m ^2=0.02 ~m ^2 aligned

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