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JEE Main 202430 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Dual Nature of Matter

JEE Main 2024 · 30 January · Evening Shift · Physics · Dual Nature of Matter

If the total energy transferred to a surface in time t is 6 . 48 ×...

If the total energy transferred to a surface in time tt is 6.48×105J6 . 48 \times {10}^{5}J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :

Options

  1. A2.46×10−3kgms−12 . 46 \times {10}^{- 3}kgm{s}^{- 1}
  2. B2.16×10−3kgms−12 . 16 \times {10}^{- 3}kgm{s}^{- 1}
  3. C1.58×10−3kgms−11 . 58 \times {10}^{- 3}kgm{s}^{- 1}
  4. D4.32×10−3kgms−14 . 32 \times {10}^{- 3}kgm{s}^{- 1}

Correct answer

B. 2.16×10−3kgms−12 . 16 \times {10}^{- 3}kgm{s}^{- 1}

Step-by-step solution

As we know,

p=Ec,p = \dfrac{E}{c}, where cc is velocity of light.

Therefore, p=6.48×1053×108=2.16×10−3kgms−1p = \dfrac{6 . 48 \times {10}^{5}}{3 \times {10}^{8}} = 2 . 16 \times {10}^{- 3}kgm{s}^{- 1}

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