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Two sources of light emit with a power of 200 W . The ratio of number of photons of visible light emitted by each source having wavelengths 300 nm and 500 nm respectively, will be :

Options

  1. A1 : 5
  2. B1 : 3
  3. C5 : 3
  4. D3 : 5

Correct answer

D. 3 : 5

Step-by-step solution

Let n 1 and n 2 be the number of photons coming out from the first and the second source of light respectively per second. So, for the first source, n 1 × h c λ 1 = 200 . . . 1 And, for the second source, n 2 × h c λ 2 = 200 . . . 2 From equations (1) and (2), it implies that n 1 n 2 = λ 1 λ 2 = 300 500 ⇒ n 1 n 2 = 3 5

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