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The difference between threshold wavelengths for two metal surfaces A and B having work function ϕ A = 9 eV and ϕ B = 4 . 5 eV in nm is: Given, h c = 1242 eV nm

Options

  1. A540
  2. B276
  3. C264
  4. D138

Correct answer

D. 138

Step-by-step solution

The work function is given by h c λ = ϕ ⇒ λ = h c ϕ By the given data, λ A = 1242 9   nm , λ B = 1242 4 . 5   nm , The difference between the wavelengths, λ B - λ A = 1242 4 . 5 - 1242 9   nm = 1242 9   nm = 138   nm

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