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JEE Main20236 Apr 2023Morning ShiftPhysicsDual Nature of MatterActual

The kinetic energy of an electron, α - particle and a proton are given as 4 K , 2 K and K respectively. The de-Broglie wavelength associated with electron ( λ e ) , α - particle ( λ α ) and the proton ( λ p ) are as follows:

Options

  1. Aλ α = λ p > λ e
  2. Bλ α < λ p < λ e
  3. Cλ α = λ p < λ e
  4. Dλ α > λ p > λ e

Correct answer

B. λ α < λ p < λ e

Step-by-step solution

The formula to calculate the de Broglie wavelength of a particle is given by λ = h 2 m K       . . . 1 Now, the masses of the given particles are interrelated by the following relations: m e ≈ m p 1837 m α = 4 m p The de Broglie wavelength for electron is given by λ e = h 2 m e 4 K =   h 8 1837 m p K       . . . 2 The de Broglie wavelength for proton is given by λ p = h 2 m p 2 K =   h 4 m p K       . . . 3 And, the de Broglie waveleng

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