JEE Main20236 Apr 2023Morning ShiftPhysicsDual Nature of MatterActual
The kinetic energy of an electron, α - particle and a proton are given as 4 K , 2 K and K respectively. The de-Broglie wavelength associated with electron ( λ e ) , α - particle ( λ α ) and the proton ( λ p ) are as follows:
Options
- Aλ α = λ p > λ e
- Bλ α < λ p < λ e
- Cλ α = λ p < λ e
- Dλ α > λ p > λ e
Correct answer
B. λ α < λ p < λ e
Step-by-step solution
The formula to calculate the de Broglie wavelength of a particle is given by λ = h 2 m K       . . . 1 Now, the masses of the given particles are interrelated by the following relations: m e ≈ m p 1837 m α = 4 m p The de Broglie wavelength for electron is given by λ e = h 2 m e 4 K =   h 8 1837 m p K       . . . 2 The de Broglie wavelength for proton is given by λ p = h 2 m p 2 K =   h 4 m p K       . . . 3 And, the de Broglie waveleng