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JEE Main202324 Jan 2023Evening ShiftPhysicsDual Nature of MatterActual

An α particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:

Options

  1. Aλ α > λ p > λ e
  2. Bλ α < λ p < λ e
  3. Cλ α = λ p = λ e
  4. Dλ α > λ p < λ e

Correct answer

B. λ α < λ p < λ e

Step-by-step solution

As we know, de-Broglie wavelength is given by, λ = h p and p = 2 m K Therefore, λ = h 2 m K As kinetic energy is the same for all particles, ∴ λ ∝ 1 m ∵ m α > m p > m e λ e > λ p > λ α

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