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The equation λ = 1 . 227 x nm can be used to find the de-Broglie wavelength of an electron. In this equation x stands for : Where, m = mass of electron P = momentum of electron K = Kinetic energy of electron V = Accelerating potential in volts for electron

Options

  1. Am K
  2. BP
  3. CK
  4. DV

Correct answer

D. V

Step-by-step solution

The de-Broglie's wavelength is given by λ = h m v , where, h is Planck's constant and v is velocity. Using relation between momentum and kinetic energy, we have λ = h 2   m KE Here, kinetic energy of electron is stated as K E = q V . Then, we have λ = h 2 m q V Putting the values of m = 9 . 1 × 10 - 31   kg   and   q = 1 . 62 × 10 - 19   C of electron We get, λ = 1 . 22 V   nm . So, x stand for V .

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