A nucleus of mass M at rest splits into two parts having masses M ^...

Since the initial momentum of the system is zero. To keep the final momentum zero, the momentum of both parts should be equal and opposite in direction.

$\left|\overset{\to}{P}1\right| = \left|\overset{\to}{P}2\right|</p><p>Here$\overset{\to}{P}$is momentum</p><p>De-Broglie wavelength is given by$\lambda = $\dfrac{h}{P}</p><p>Hence, both will have same de Broglie wavelength.</p><p>Therefore,${\lambda}_{1}: {\lambda}_{2} = 1: 1$.</p></blockquote>$