JEE Main202225 Jun 2022Evening ShiftPhysicsDual Nature of MatterActual
A proton, a neutron, an electron and an α -particle have same energy. If λ p , λ n , λ e and λ α are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following
Options
- Aλ p = λ n > λ e > λ α
- Bλ a < λ n < λ p < λ e
- Cλ e < λ p = λ n > λ α
- Dλ e = λ p = λ n = λ α .
Correct answer
B. λ a < λ n < λ p < λ e
Step-by-step solution
The de-Broglie wavelength λ   =   h 2 m ( K . E . ) where, h and K . E . are constant λ ∝ 1 m m = Mass of the particle Thus, with increasing mass of particle de-Broglie wavelength decreases. Order of mass m e < m p < m n < m α Order of de-Broglie wavelength is λ a < λ n < λ p < λ e