The temperature of an ideal gas in three dimensions is 300 K . The corresponding de-Broglie wavelength of the electron approximately at 300 K is: m e = mass of electron = 9 × 10 - 31 kg , h = Planck constant = 6 . 6 × 10 - 34 J s , k B = Boltzmann constant = 1 . 38 × 10 - 23 J K - 1

Step-by-step solution

k = 1 . 38 × 10 - 23   J   K - 1 Mass of electron = 9 × 10 - 31   kg ⇒ λ D = h 2 m × 3 2 × k T = h 3 mkT ⇒ λ D = 6 . 6 × 10 - 34 3 × 9 × 10 - 31 × 1 . 38 × 10 - 23 × 300 = 6 . 6 × 10 - 34 105 . 72 × 10 - 27 = 62   A ο Thus x = 62   A ο