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JEE Main202125 Feb 2021Evening ShiftPhysicsDual Nature of MatterActual

The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 491 nm is 0 . 710 V . When the incident wavelength is changed to a new value, the stopping potential is 1 . 43 V . The new wavelength is :

Options

  1. A382   nm
  2. B309   nm
  3. C329   nm
  4. D400   nm

Correct answer

A. 382   nm

Step-by-step solution

h c λ = ϕ + e V s 1240 491 = ϕ + 0 . 71             . . . 1 1240 λ = ϕ + 1 . 43             . . . 2 ∴ λ = 382   nm

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