JEE Main202125 Feb 2021Evening ShiftPhysicsDual Nature of MatterActual
The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 491 nm is 0 . 710 V . When the incident wavelength is changed to a new value, the stopping potential is 1 . 43 V . The new wavelength is :
Options
- A382   nm
- B309   nm
- C329   nm
- D400   nm
Correct answer
A. 382   nm
Step-by-step solution
h c λ = ϕ + e V s 1240 491 = ϕ + 0 . 71             . . . 1 1240 λ = ϕ + 1 . 43             . . . 2 ∴ λ = 382   nm