A beam of electrons of energy E scatters from a target having atomic spacing of $1Å$ . The first maximum intensity occurs at $\theta = 60 ° .$ Then $E ( ineV )$ is........
(Planck's constant $h = 6 . 64 \times {10}^{- 34}Js, 1eV = 1 . 6 \times {10}^{- 19}J,$ electron mass $m = 9 . 1 \times {10}^{- 31}kg$ )

Question

A beam of electrons of energy E scatters from a target having atomic spacing of

1Å

. The first maximum intensity occurs at

\theta = 60 ° .

Then

E ( ineV )

is........
(Planck's constant

h = 6 . 64 \times {10}^{- 34}Js, 1eV = 1 . 6 \times {10}^{- 19}J,

electron mass

m = 9 . 1 \times {10}^{- 31}kg

)

Quantrex Academy · Accepted Answer

Correct answer: 50

2dsinθ = nλ 2d 3 2 = (1)λ d = 1Å λ = 3 Å λ = 3 = (150)/(V) V = 50volt E = 50eV

A beam of electrons of energy E scatters from a target having...